# [Answer] What is the net force on an object in either static or dynamic equilibrium?

###### Answer: The net force is zero
What is the net force on an object in either static or dynamic equilibrium?

Thus the net force on the object is the difference between the magnitudes of the buoyant force and its weight. If this net force is positive the object rises; if negative the object sinks; and if zero the object is neutrally buoyant—that is it remains in place without either rising or sinking.

Statics is the branch of mechanics that is concerned with the analysis of loads (force and torque or “moment”) acting on physical systems that do not experience an acceleration (a=0) but rather are in static equilibrium with their environment. The application of Newton’s second law to a system gives: ${\textbf {F}}=m{\textbf {a}}\ .$ Where bold font indicates a vector that has magnitude and direction. ${\textbf {F}}$ is the total of the forces acting on the system $m$ is the mass of t…

Statics is the branch of mechanics that is concerned with the analysis of loads (force and torque or “moment”) acting on physical systems that do not experience an acceleration (a=0) but rather are in static equilibrium with their environment. The application of Newton’s second law to a system gives: ${\textbf {F}}=m{\textbf {a}}\ .$ Where bold font indicates a vector that has magnitude and direction. ${\textbf {F}}$ is the total of the forces acting on the system $m$ is the mass of the system and ${\textbf {a}}$ is the acceleration of the system. The summation of forces will give the direction and the magnitude of the acceleration and will be inversely proportional to the mass. The assumption of static equilibrium of ${\textbf {a}}$ = 0 leads to: ${\textbf {F}}=0\ .$ The summation of forces one of which might be unknown allows that unknown to be found. So when in static equilibrium the acceleration of the system is zero and the system is either at rest or its center of mass moves at constant velocity. Likewise the application of the assumption of zero acceleration to the summation of moments acting on the system leads to: ${\textbf {M}}=I\alpha =0\ .$ Here ${\textbf {M}}$ is the summation of all moments acting on the system $I$ is the moment of inertia of the mass and $\alpha$ = 0 the angular acceleration of the system which when assumed to be zero leads to: ${\textbf {M}}=0\ .$ The summation of moments one of which might be unknown allows that unknown to be found. These t…

Dynamic equilibrium – Wikipedia

Statics – Wikipedia

An object resting on a surface and the corresponding free body diagram showing the forcesacting on the object. The normal force N is equal opposite and collinear to the gravitational force mg so the net force a…